$A$ body,under the action of a force $\vec F = 6\hat i - 8\hat j + 10\hat k$,acquires an acceleration of $1\, m/s^2$. The mass of this body must be

$A$ body of $5 \, kg$ is moving with a velocity of $20 \, m/s$. If a force of $100 \, N$ is applied on it for $10 \, s$ in the same direction as its velocity,what will be the final velocity of the body in $m/s$?

$A$ force of $6 \; N$ acts on a body at rest and of mass $1 \; kg$. During this time,the body attains a velocity of $30 \; m/s$. The time for which the force acts on the body is ..... $seconds$.

$A$ force $\vec{F}=(40 \hat{i}+10 \hat{j}) \, N$ acts on a body of mass $5 \, kg$. If the body starts from rest,its position vector $\vec{r}$ at time $t=10 \, s$ will be -

$A$ bullet of mass $20 \,g$ moving with $500 \,ms^{-1}$ is pierced $1 \,cm$ into a wooden block. The retarding force experienced by the bullet is:

$A$ body of mass $2 \, kg$ is moving with a velocity $8 \, m/s$ on a smooth surface. If it is to be brought to rest in $4 \, seconds$,then the force to be applied is ......... $N$.